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  • What is the difference between * arr and * arr[0] in C++, if arr is an . . .
    1 Suppose I have an array of integers called arr I am trying to understand the distinction between * arr and * arr[0] I read that in C++, arr is essentially a pointer to the first element in the array and arr is a pointer to the whole array They both return the same address, I get this part
  • What is the meaning of arr [:] in assignment in numpy?
    Your question involves a mix of basic Python syntax, and numpy specific details In many ways it is the same for lists, but not exactly arr[:, 0] returns the 1st column of arr (a view), arr[:,0]=10 sets the values of that column to 10 arr[:] returns arr (alist[:] returns a copy of a list) arr[:]=arr2 performs an inplace replacement; changing the values of arr to the values of arr2 The
  • Understanding arr[::-1] in numpy. Is this a special case?
    In fact it is just interpreting that it needs to go till the boundary as arr [::1] gives normal array Is this just coded as a special case or is there something more going on?
  • c - What does *arr [] mean? - Stack Overflow
    what does *arr[] mean? As standalone expression *arr[] is not valid For variable definitions there are two meanings here, depending of the context in which such an expression appears: Variable definition with initialiser (as per the OP's snippet) int * arr[] = { m[0], m[1], m[2] }; This defines an array of pointer to int, with its number of elements being determined by the number of elements
  • Why does i[arr] work as well as arr[i] in C with larger data types?
    0 arr is declared as the array of 4 structures with each structure comprising of a char array of 1024 chars arr is resolved as the pointer to the first element to this array of structures When you increment arr by 1, this new pointer, will skip one whole structure ( the type to which it points ) and then points to the next element in the array
  • c - Difference between *arr [] and **arr - Stack Overflow
    Theoretically, *arr[] and **arr are different For example : char *arr[size]; case 1 Here arr is a an array of size size whose elements are of the type char* Whereas, char **arr; case2 Here arr is itself a pointer to the type char* Note: In case 1 array arr degrades to a pointer to become the type char** but it's not possible the other way around i e, pointer in case 2 cannot become an array
  • How does *( arr + 1) - arr give the length in elements of array arr?
    The trick is to use the expression ( arr) [1] - arr to get the array arr size Both arr and arr points to the same memory location, but they both have different types
  • How *( arr + 1) - arr is working to give the array size
    As others have mentioned, *( arr + 1) triggers undefined behavior because arr + 1 is a pointer to one-past-the end of an array of type int [7] and that pointer is subsequently dereferenced
  • What does arr [:, [1,0,2] means in the snippet of code?
    here [1,0,2] takes the order in which columns of the arr should be re-arranged i e the column at index [1] , then column at index [0] and finally the column at index [2] should be ordered while rows' order remains the same
  • Accessing HTTP resource on HTTPS IIS Site with ARR Proxy Setting
    Accessing HTTP resource on HTTPS IIS Site with ARR Proxy Setting Asked 4 years, 11 months ago Modified 4 years, 11 months ago Viewed 1k times





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