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  • Understanding Python super() with __init__() methods
    The primary difference in this code is that in ChildB you get a layer of indirection in the __init__ with super, which uses the class in which it is defined to determine the next class's __init__ to look up in the MRO I illustrate this difference in an answer at the canonical question, How to use 'super' in Python?, which demonstrates dependency injection and cooperative multiple inheritance
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    super () is a special use of the super keyword where you call a parameterless parent constructor In general, the super keyword can be used to call overridden methods, access hidden fields or invoke a superclass's constructor
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    It wasn't what I expected when I read this line right before the example: If we're using a class method, we don't have an instance to call super with Fortunately for us, super works even with a type as the second argument --- The type can be passed directly to super as shown below Which is exactly what Python tells me is not possible by saying that do_something () should be called with an
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    This technique can be extended If super takes many parameters or you need to set other fields at the same time, create a static inner class to hold all variables, and use it to pass data from the static method to the single-arg constructor
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    There is an implicit call to super () with no arguments for all classes that have a parent - which is every user defined class in Java - so calling it explicitly is usually not required However, you may use the call to super () with arguments if the parent's constructor takes parameters, and you wish to specify them
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    I have created an Android Application Project and in MainActivity java > onCreate() it is calling super onCreate(savedInstanceState) As a beginner, can anyone explain what is the purpose of the a
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